Let the line segments ab and cd intersect at o in such a way that equals to audi and ab = ac prove that is equals to bd but ac may not be parallel to bd
Answers
Answered by
83
Given, OA = OD and OB = OC
To prove: AC = BD and AC mayn't be parallel to BD.
Proof:
In Δ AOC and Δ BOD, we have
OA = OD [given]
∠COA = ∠DOB [vertically opposite angles]
OB = OC [given]
⇒ Δ AOC Δ BOD [SAS congruency]
⇒ AC = BD [c.p.c.t]
Again, ∠OAC = ∠ODB [c.p.c.t]
and ∠OCA = ∠OBD [c.p.c.t]
Therefore, ∠OAC may not be equal to ∠OBD.
Hence, AC may not be parallel to BD.
[Hence proved]
To prove: AC = BD and AC mayn't be parallel to BD.
Proof:
In Δ AOC and Δ BOD, we have
OA = OD [given]
∠COA = ∠DOB [vertically opposite angles]
OB = OC [given]
⇒ Δ AOC Δ BOD [SAS congruency]
⇒ AC = BD [c.p.c.t]
Again, ∠OAC = ∠ODB [c.p.c.t]
and ∠OCA = ∠OBD [c.p.c.t]
Therefore, ∠OAC may not be equal to ∠OBD.
Hence, AC may not be parallel to BD.
[Hence proved]
Answered by
28
Answer:
Step-by-step explanation:
Given, OA = OD and OB = OC
To prove: AC = BD and AC mayn't be parallel to BD.
Proof:
In Δ AOC and Δ BOD, we have
OA = OD [given]
∠COA = ∠DOB [vertically opposite angles]
OB = OC [given]
⇒ Δ AOC Δ BOD [SAS congruency]
⇒ AC = BD [c.p.c.t]
Again, ∠OAC = ∠ODB [c.p.c.t]
and ∠OCA = ∠OBD [c.p.c.t]
Therefore, ∠OAC may not be equal to ∠OBD.
Hence, AC may not be parallel to BD.
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