Question

let the memory access time is 10million second and cache hit ratio 15% the effective memory access time is?

Answer 1

Given:

cache access time is 7 ns, m

ain memory access time is 50 ns

disk space access time is 1200 ns.

hit rate of cache is 60%

main memory hierarchy is 70 percent,

Asked :

the average memory access time is

Sol:

Avg Time:

Hit in Cache * Access(cache)+ MissCache * Hit Main* ( Access Main+Access Cache)+MissCache* MissMain (Accesscache+AccessMain+AccessDisk)

=>0.6*7+0.4*0.7*(50+7)+0.4*0.3(7+50+1200)

=>4.2+0.28*57+0.12*1257

=>4.2+15.96+150.84

=>171

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Answer 2

Answer: Time to access TLB = 2 ns. Main memory access time = 60ns. External cache access time = 20 ns.

teff=tTLB+(1−hitTLB)(tseg+tpage)+tcache+(1−hitcache)tRAM

=2+0.02(20+20+0.5∗60)+20+0.08∗60=28.2 ns.

Explanation: