Question

let the object of the mass m be made to be freeely fallen from the height h what will be it's potential and kinetic energy at the start​

Answer 1

Answer:

Kinetic energy is zero i.e. K=0

Potential energy U=mg(x+y)

Total energy T=U+K=mg(x+y)

Point B :

Velocity v=

2g(x)

Kinetic energy K=

2

1

mv

2

=mg(x)

Potential energy U=mg(y)

Total energy T=U+K=mg(x+y)

Point C :

Velocity v=

2g(x+y)

Kinetic energy K=

2

1

mv

2

=mg(x+h)

Potential energy U=0

Total energy T=U+K=mg(x+y)

The above parts verifies the law of conservation of energy.

Answer 2

Explanation:

please j.o.i.n waiting for you

ryb-duvt-iqkp