Let the period of revolution of a planet at a distance r from star .prove that if it was at a distance of 2R from the start, it's period of revolution will be 8 T
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hii mate!!
❄According to Kepler's law , T²a³
Here T denotes the time period and a denotes the distance between two objects
Here, when distance between planet and star is R then time period is T
means T² = kR³ [ here k is proportionality constant ]----(1)
↪Again, Let the time period is T' when distance between planet and star is 2R
T'² = k(2R)³ = k.8R³ -----(2)
Dividing equation (1) by (2)
T²/T'² = kR³/k8R³ = 1/8
T'² = 8T²
square root both sides,
T' = T
↪Hence, time period will be T , when distance between planet and star will be 2R.
hope it helps !!☺☺
❄According to Kepler's law , T²a³
Here T denotes the time period and a denotes the distance between two objects
Here, when distance between planet and star is R then time period is T
means T² = kR³ [ here k is proportionality constant ]----(1)
↪Again, Let the time period is T' when distance between planet and star is 2R
T'² = k(2R)³ = k.8R³ -----(2)
Dividing equation (1) by (2)
T²/T'² = kR³/k8R³ = 1/8
T'² = 8T²
square root both sides,
T' = T
↪Hence, time period will be T , when distance between planet and star will be 2R.
hope it helps !!☺☺
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