Let the position vectors of the points P. Q and R are respectively given by 21i+5i-8k, 3j+6k and
-3i+2j+3k. If PQRS is a parallelogram, find the equation of QS in cartesian and vector form.
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AC = AB+BC = i+j+k-2i+j+2k = -i+2j+3k
therefore MOD AC = ROOT OVER OF (-1)^2+2^2+3^2=ROOT OVER OF 14
THEREFORE UNIT VECTIR PARALLEL TO DIAGONAL AC OF THE PARALLELOGRAM ABCD IS = AC/MOD AC =1/ ROOT14×(-i+2j+3k
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Dear your answer is given in the attachment.
it will help u
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