Question

Let the potential energy of hydorgen atom in the ground state be zero. Then its total
excited state will be
2) 238 eV
b) 27.2 eV
c) 3.4 eV
d) 13.6​

Answer 1

Explanation:

$\huge\tt\underline\red{Solution\::-}$

Making potential energy zero increase the value of energy by

$13.6 - ( - 13.6) = 27.2eV$

Now, actual energy in second orbit

= –3.4eV

Hence, new value is

$( - 3.4 + 27.2)eV \: = 23.8eV$

Opt. (a) will be your answer.

PLEASE FOLLOW ME....