Let the radius of a circle be 25.2cm. Find the area of semicircle, perimeter of the quadrant?
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Given : radius of a circle be 25.2cm
To Find : area of semicircle,
perimeter of the quadrant
Solution:
Area of semicircle, = (1/2) πr²
r = radius = 25.2 cm
π = 22/7
Area of semicircle, = (1/2)(22/7)(25.2)²
= 997.92 cm²
perimeter of the quadrant = r + r + (1/4) 2πr
= 2r + πr/2
= 2 * 25.2 + (22/7)*25.2/2
= 50.4 + 39.6
= 90 cm
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