LET THE RATIO BETWEEN TWO SUPPLEMENTARY ANGLES BE 2:3 THEN FIND THE ANGLES
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Answered by
2
The sum supplementary angles is 180° Let the angles be 2x and 3x
3x+2x= 180°
5x= 180°
x=180°\5
x= 36°
so, 2x= 2*36 = 72°
3x= 3*36= 108°
Hope it helps..^_^
3x+2x= 180°
5x= 180°
x=180°\5
x= 36°
so, 2x= 2*36 = 72°
3x= 3*36= 108°
Hope it helps..^_^
tulikas1407:
pleasure is all mine
i got another Q in triangles
oh what's it..
AD is median of triangle ABC ,AB=CD & BD=DC find angle ADB
this can be prooved by congruenting triagngles ABD and ADC in which AB=CD (given)and AD=AD( common) and BD= CD (given) so by SSS congruence these two triangles are congruent and |_ ADB=|_ ADC (by cpct).
|_ ADB+|_ ADC =180° (linear pair)
2|_ADB= 180°
|_ ADB= 180°\2= 90°
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wlcm...:-)
Answered by
1
Heya,
Supplementary angle means that sum of angel should be equal to 180°
The ratio of angel given is 2:3
Let first Angel be = 2x
And second Angle be = 3x
So,
=> 2x + 3x = 180°
=> 5x = 180°
=> x = 180°/5
=> x = 36°
Now,
The first Angel = 2×36°
= 72°
Second Angle = 3×36°
= 108°
So, the two Angels are 72° and 108°.
Hope this helps...:)
Supplementary angle means that sum of angel should be equal to 180°
The ratio of angel given is 2:3
Let first Angel be = 2x
And second Angle be = 3x
So,
=> 2x + 3x = 180°
=> 5x = 180°
=> x = 180°/5
=> x = 36°
Now,
The first Angel = 2×36°
= 72°
Second Angle = 3×36°
= 108°
So, the two Angels are 72° and 108°.
Hope this helps...:)
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