Let the ratio of water and milk be 1:4 in a filled can of capacity 100 litres. the mixture was added with more water so as to change the ratio of 3:8. find the quantity of water present originally and the amount of water (in litres) added thereafter.
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The sum of the ratios is :
1 + 4 = 5
The amount of water in the mixture is :
1/5 × 100 = 20 lites
Amount of milk is :
100 - 20 = 80litres
Let the added amount of water be x then the new volume is :
20 + x
The new ratio is :
20 + x : 80 = 3 : 8
20 + x / 80 = 3/8
8(x + 20) = 3 × 80
8x + 160 = 240
8x = 240 - 160
8x = 80
x = 80/8
x = 10 litres
The amount added is thus 10 litres
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