Let the refractive index of a denser medium with respect to a rarer medium be n12and its c critical angle be c.At an angle of incidence a when light is travelling from denser medium to rarer medium, a part of the light is reflected and the rest is refracted and the angle between reflected and refracted rays is 90. Angle a given by
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Answer:
n
12
=
n
r
n
d
sin90
sinθ
=
n
3
n
2
sinR
sini
=
n
1
n
2
sini=sinr
sinR
sinr
=
n
1
n
2
=
sin90
sinθ
c
cosr
sinr
=sinθ
c
cosr
tanr=sinθ
c
r=tan
−1
(sinθ
c
)
Explanation:
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