Let the resistance of an clectrical component remains constante
the potential difference across the two ends of the component decreases
to half of its former value. What change will occur in the current through
it?
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As per ohm's law, V=IRI= RV ....(i)Potential difference is halfV 1 = 2V ∴I 1 = RV 1 R2V = 21 2V = 21 (I)= 2I ∴ current flowing is also half of ts former value.
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