Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to one fourth of its former value. What change will occur in the current through it?
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Answer:
Current will be 4 times greater
Explanation:
Resistance of a component
R = V ( potential difference) ÷ I (Current)
According to the condition,
Provided R is a constant,
R = V' ÷ I, where V' = V ÷ 4
=> R = (V ÷ 4) ÷ I
= ¼ of V ÷ I
or R = V ÷ 4×I
Thus, the current will be 4 times than that of the earlier.
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