Question

Let the resistance of an electrical component remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occur in the current through it?

Answer 1

we know V=IR.
R=V/I
now V becomes half
so to keep R constant or the ratio V/I constant,
I increase 2 times
R=V/2 ÷2I

that's it :)

Answer 2

The current in such a situation will also decrease to half of its former value.

• According to the equation of Ohm's law, V = IR

         where, V = Potential difference

                      I = Current

                     R = Resistance

• Since it is given in the question that the resistance of the electrical component remains constant, therefore V ∝ I.
• Therefore, as the potential difference V reduces to half of its former value, so does the value of current (I).