Question

let the resistance of an electrical compound remains constant while the potential difference across the two ends of the component decreases to half of its former value. What change will occurs in the current through it?

Answer 1

Ans: According to Ohm’s law

V = IR

⇒ I=V/R ---------- (1)

Now Potential difference is decreased to half

∴ New potential difference Vʹ=V/2

Resistance remains constant

So the new current Iʹ = Vʹ/R

                            = (V/2)/R

                            = (1/2) (V/R)

                            = (1/2) I = I/2

Answer 2

According to ohm's law,

V=IR------(1)
When potential difference is decreased to half=V'=V/2
The original and the resistance after potential difference is halved remains the same=R