let the resistence of an electrical component remains constant while the potential difference across the two ends of the component decrease to half of its former value. what change will occur in the current through it ?
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According to Ohms law, it will also get reduced by half
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We know that according to Ohm’s law
V = IR
where
V= potential difference
I= Current
R = Resistance
We can also modify the equation as
I=V/R ——- (i)
Now given that the potential difference across the two ends of the component decreases to half
∴ So let the new potential difference be Vʹ=V/2
Resistance remains constant across the electrical component
So the new current is drawn through the electrical component is Iʹ = Vʹ/R
= (V/2)/R {Substituting Vʹ=V/2 in the above equation}
= (1/2) (V/R)
= (1/2) I = I/2
Therefore, the amount of current flowing through the electrical component is reduced by half.
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