let the resultant of three forces of magnitude 5 n, 12 n and 13 n acting on a body be zero.if sin23=5/13 find the angle between the 5 n force and 13n force.
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Answer:
90-23=67
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the angle between the 5 n force and 13n force. = 113°
Explanation:
the angle between the 5 n force and 13n force. = α
5² + 13² + 2(5)(13)Cosα = 12²
=> 25 + 169 +2(5)(13)Cosα = 144
=> 2(5)(13)Cosα = - 50
=> Cosα = -5/13
Sinβ= - Cos(90 + β)
sin23°=5/13
=> -Cos 113° = 5/13
=> Cos 113° = -5/13
α = 113°
the angle between the 5 n force and 13n force. = 113°
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