let the sequence an be defined as follows: a1=1 , an-1 +2 for n≥2. find first 5 terms and write corresponding series
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Answer:- Given,
Given,a
Given,a 1
Given,a 1
Given,a 1 =2
Given,a 1 =2a
Given,a 1 =2a n
Given,a 1 =2a n
Given,a 1 =2a n =a
Given,a 1 =2a n =a n−1
Given,a 1 =2a n =a n−1
Given,a 1 =2a n =a n−1 +2 for n≥2
Given,a 1 =2a n =a n−1 +2 for n≥2a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2
Given,a 1 =2a n =a n−1 +2 for n≥2a 2
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a 4
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a 4
Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a 4 +2=10
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