Math, asked by saijagsn1605, 5 months ago

let the sequence an be defined as follows: a1=1 , an-1 +2 for n≥2. find first 5 terms and write corresponding series​

Answers

Answered by Monikastudent
1

Answer:- Given,

Given,a

Given,a 1

Given,a 1

Given,a 1 =2

Given,a 1 =2a

Given,a 1 =2a n

Given,a 1 =2a n

Given,a 1 =2a n =a

Given,a 1 =2a n =a n−1

Given,a 1 =2a n =a n−1

Given,a 1 =2a n =a n−1 +2 for n≥2

Given,a 1 =2a n =a n−1 +2 for n≥2a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2

Given,a 1 =2a n =a n−1 +2 for n≥2a 2

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a 4

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a 4

Given,a 1 =2a n =a n−1 +2 for n≥2a 2 =a 1 +2=4a 3 =a 2 +2=6a 4 =a 3 +2=8a 5 =a 4 +2=10

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