Question

Let the sets be A = {x: x is a real root of equation (x2 - 5x +
6)-(x2 - 12x + 35) = 0} and B = {1, 2, 3, 4, 5), then the number
of ordered pairs in (A x B) n (B A) is​

Answer 1

A

Only I

B

Only I and III

C

Only II

D

Only II and III

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ANSWER

P(X)=x2+ax+b                a,b∈R

Roots are real

g(x)=p(x3)4

x3=t

g(x)=p(t)

p(t)=t2+at+b

Roots are real but t=x3

Let t=β

      x3=β

      x=(β)31,(β31)w,(β31),w2

Only 1 real root, 2−image.

Same are other roots

t=γ

It has only one real root

Total