Let the sum of the first three terms of an A.P. be 39 and the sum of its last four terms be 178. If the first term of this A.P. is 10, then the median of the A.P. is :
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Given:
sum of the first three terms is 39
sum of the last four terms is 179
if the first term is 10, then the median of the A.P is:
10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49
10 + 13 + 16 = 39
40 + 43 + 46 + 49 = 178
A.P or arithmetic progression is a sequence of numbers that have a common difference. In the above set, the common difference is 3.
10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49
median = 28+31 = 59/2 = 29.50
sum of the first three terms is 39
sum of the last four terms is 179
if the first term is 10, then the median of the A.P is:
10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49
10 + 13 + 16 = 39
40 + 43 + 46 + 49 = 178
A.P or arithmetic progression is a sequence of numbers that have a common difference. In the above set, the common difference is 3.
10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49
median = 28+31 = 59/2 = 29.50
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