Math, asked by hiramani8432, 10 months ago

Let the three consecutive multiple of 11 is 363 . Find the multiples? Done

Answers

Answered by mhanifa
0

Answer:

110, 121, 132

Step-by-step explanation:

Let the numbers be a, b and c

  • a=11x
  • b=11(x+1)= 11x+11
  • c=11(x+2)= 11x=22

Then sum is:

  • a+b+c=363
  • 11x+11x+11+11x+22=363
  • 33(x+1)=363
  • x+1=11
  • x=10

Numbers are

a=110, b=121, c=132

Answered by dheryamittal
0

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.

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