Question

Let the three consecutive multiple of 11 is 363 . Find the multiples? Done

Answer 1

Answer:

110, 121, 132

Step-by-step explanation:

Let the numbers be a, b and c

• a=11x

• b=11(x+1)= 11x+11

• c=11(x+2)= 11x=22

Then sum is:

• a+b+c=363
• 11x+11x+11+11x+22=363
• 33(x+1)=363
• x+1=11
• x=10

Numbers are

a=110, b=121, c=132

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.