Question

let the three no. are in AP (x-1),(x+2),(x-7) find the value of x

Answer 1

Three numbers (x-1), (x+2) and (x-7) are in A.P

So, now because each of these consecutive terms when subtracted from each other would give us a common difference, thus we can write
(x-7) - (x+2) = (x+2)-(x-1)
2(x+2)= (x-1)+(x-7)
2x + 4 = 2x - 8
We can clearly see here, that this equation does not hold true for any possible real value of x
Therefore , there will be no value of x satisfying the given condition.

Hope this helps you !

Answer 2

Answer:

Step-by-step explanation: