Question

Let the vectors $a$ & $b$ be such that $|a|$ = 5 and $|b|$ = $\sqrt{2} \div 5$ & if $a \times b$ is a unit vector, then find the angle between $a$ & $b$.​

Answer 1

$\huge\boxed{\fcolorbox{white}{magenta}{Answer}}$

Angle between two vectors :-

$\Large\boxed{cos(x)°=a•b/|a||b|}$

$\Large\boxed{a•b=|a×b|}$

=> cosx = 1 / (5 × √2/5)

=> cosx = 1 / √2

$\Large\boxed{x=45°}$

i hope this will helps u bro...☺️

Answer 2

Angle between two vectors :-

=> cosx = 1 / (5 × √2/5)

=> cosx = 1 / √2

\Large\boxed{x=45°}x=45°

i hope this will helps u