Math, asked by abhishekblacksharkof, 21 hours ago

let the zeroes of the polynomial 3x2-8x+2k+1 be alpha, beta
please help​

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Answers

Answered by clementcherian
0

Answer: The value of k is 2 by 3

Step-by-step explanation:

Consider the given quadratic polynomial to be f(x),



f(x)=3x

2

−8x+2k+1



Given one zero of the polynomial is seven times another.



α=α

β=7α



Using the sum of zeroes formula,



sum​of​zeroes(α+β)=−

Coefficient​of​x

Coefficient​of​x

​2

α+7α=−

(−8)

3

8α=

8

3

α=

1

3





β=7α

β=7×

1

3

β=

7

3



Using product of zeroes formula,



product​of​zeroes(αβ)=

constant​term

coefficient​of​x

​2

1

3

×

7

3

=

2k+1

3

7=3(2k+1)

7=6k+3





6k=4

k=

2

3



Answered by manojkumar14831733
0

Answer:

bro such a big question I can't answer sorry

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