Question

Let there are 4 red, 3 yellow and 2 green balls, then total number of arrangements in a row such that no two balls of same colour are together (balls of same colour are identical) are

Answer 1

According to question


Number of Red Balls = 4\
Number of Yellow Balls = 3
Number of Green Balls = 2

SO total Balls = 4 + 3 + 2
                            = 9 Balls

thus as per the condition

Probabilty = 9 C2
                  = 8