Let there be an A.P. with first term 'a', common difference 'd'. If an denotes its nth term and Sn the sum of first n terms, then find n and Sn, if a=5, d=3, and an=50
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Answer:
16&440
Step-by-step explanation:
a=5
d=3
an=50
an=a+(n-1)d
50=5+(n-1)3
50= 5+3n-3
50=2+3n
48=3n
16=n
sn = n/2(2a+(n-1)d)
16/2(2×5+(16-1)3)
8(10+15×3)
8(10+45)
8×55
440
hope it helps
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