Let there be an ap with first term as 'a' common difference as 'd' if an denotes it's nth term and sn the sum of the first n terms, find n and sn if a=5 d=3 an=50
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Answer:
a=5
d=3
an= 50
an= a+(n-1) d
50 = 5 +(n - 1) 3
50 = 5+ 3n - 3
50 = 2 + 3n
50 - 2 = 3n
48 = 3n
n= 48/3
n= 16
Sn = n/2(a+an)
S16 = 16/2 (5+50)
= 8(55)
S16 = 440
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