Physics, asked by Anonymous, 9 months ago

Let three capacitors of capacitance C1, C2 and C3 are connected in (a) series and (b) parallel. Derive an expression for effective resistance in both series and parallel combination

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Answered by kings07
2
Hello friend!! your answer is here..!!


capacitors in series : when capacitance are connected in series, the charge remains constant but voltage varies, so
V = V1+V2+V3.
we know that C=Q/V implies V=Q/C
therefore , 
Q/C = Q/C1 + Q/C2 + Q/C3
1/C  = 1/C1  + 1/C2  + 1/C3
is the resultant capacitance when capacitors are connected in series.

capacitors in parallel:
when capacitance are connected in parallel, then charge varies but voltage remains constant so,
Q = Q1 + Q2 + Q3 
we know that C = Q/V implies Q = CV 
therefore,
CV = C1V + C2V + C3V
implies 
C = C1 + C2 +C3
is the resultant capacitance when capacitors are connected parallel.

hope my answer is useful to you..!!


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Answered by VedankMishra
0

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