Let three capacitors of capacitance C1, C2 and C3 are connected in (a) series and (b) parallel. Derive an expression for effective resistance in both series and parallel combination
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capacitors in series : when capacitance are connected in series, the charge remains constant but voltage varies, so
V = V1+V2+V3.
we know that C=Q/V implies V=Q/C
therefore ,
Q/C = Q/C1 + Q/C2 + Q/C3
1/C = 1/C1 + 1/C2 + 1/C3
is the resultant capacitance when capacitors are connected in series.
capacitors in parallel:
when capacitance are connected in parallel, then charge varies but voltage remains constant so,
Q = Q1 + Q2 + Q3
we know that C = Q/V implies Q = CV
therefore,
CV = C1V + C2V + C3V
implies
C = C1 + C2 +C3
is the resultant capacitance when capacitors are connected parallel.
hope my answer is useful to you..!!
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capacitors in series : when capacitance are connected in series, the charge remains constant but voltage varies, so
V = V1+V2+V3.
we know that C=Q/V implies V=Q/C
therefore ,
Q/C = Q/C1 + Q/C2 + Q/C3
1/C = 1/C1 + 1/C2 + 1/C3
is the resultant capacitance when capacitors are connected in series.
capacitors in parallel:
when capacitance are connected in parallel, then charge varies but voltage remains constant so,
Q = Q1 + Q2 + Q3
we know that C = Q/V implies Q = CV
therefore,
CV = C1V + C2V + C3V
implies
C = C1 + C2 +C3
is the resultant capacitance when capacitors are connected parallel.
hope my answer is useful to you..!!
Change tx to tex
↓↓
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