let triangle ABC congruent triangle DEF and their areas be 64cm square and 121 cm square respectively.If EF = 15.4 cm ,find BC
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ABC∼△DEF
⟹Ar(ΔDEF)Ar(ΔABC)=(EFBC)212164=(15.4BC)2BC=12164×15.4BC=118×15.4=11.2cm
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above answer is correct
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