Question

Let triangle ABC is congruent to triangle DEF and their areas be 100 cm² and 49 cm2. If EF = 8.4cm find BC​ 'pls answer fast it is urgent If anyone answers I mark it as brainest answer'

Answer 1

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Answer 2

Answer:

BC = 12cm

Step-by-step explanation:

We know that,

Ratio of areas of two similar triangles is equal to the square of their corresponding sides.

$\sf{\dfrac{100}{49}}={\dfrac{{BC}^2}{{EF}^2}}$

$\sf{\sqrt{\dfrac{100}{49}}}={\dfrac{BC}{8.4}}$

$\sf{BC=}{\dfrac{84}{7}}$

$\sf{BC=12cm}$