Question

let triangle ABC similar to trangle def and their areas B respectively 64 CM square and 121 CM square if EF is equal to 15.4 cm square find BC​

Answer 1

Answer:

Step-by-step explanation:

∆ABC~∆DEF...,..........given

Now,

By similar triangle theorem we get,

∆ABC2 /∆ DEF2 = BC2 / EF2

64/121 = BC2/(15.4)2

By taking square roots of both sides,

8/11= BC/15.4

By cross multiplication,

(15.4×8)/11 = BC

BC=11.2

therefore value of BC is 11.2

Answer ☺

Answer 2

Answer:

area of triangle ABC/area of triangle DEF=BC^2/EF^2

=64/121= BC^2/(15.4)^2

=64/121= BC^2/237.16

=64 X 237.16= 121 X BC^2

=15178.24= 121 X BC^2

=15178.24/121 = BC^2

=125.44 = BC^2

=11.2 = BC