let triangle ABC similar to triangle d e f and their areas be respectively 64 CM square and 121 CM square if EF is equal to 15.4 cm find the BC
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6+6+6+6.......∞=3 .
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Let ∆ABC ~ ∆DEF and their areas be, respectively, 64 cm2 and 121 cm2. ... We know that the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides. ∴ Hence, BC = 11.2 cm.
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