Let triangle abc ~trianfledef and their areas be 64cm and 121 cm . If ef =13.2 find bc
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Step-by-step explanation: given = ∆ABC ~∆DEF
Area of ∆ABC = 64 CM
Area of ∆DEF = 121 CM
EF is equals to 13.2 cm
Therefore,
=Area of∆ABC/area of ∆DEF = BC/EF
= 64/121 = (BC/13.2)^2
=√64/121 = BC / 13.2
= 8/11 = BC /13.2
= BC = 13.2*8/11
= BC = 9.6
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