let triangle abc ~ triangle def and their areas be 64 cm2 and 121 cm2 . if ef =15.4 cm , find bc
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hope u get the answer
btw merry xmas
btw merry xmas
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Heyy mate ❤✌✌❤
Here's your Answer...
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Ar(ABC)/Ar(DEF) = 64/ 121 --------(1)
As we know that, The Ratio of Similar triangle is equal to the square of the ratio pf yheir side.
=> AB/EF = (X/ 15.4)^2 -------(2)
FROM EQUATION 1 AND 2.
=> 64/121 = (X/15.4)^2
=> 8/ 11= X / 15.4
=> X = 15.4 × 8/11
=> x = 11.2cm✔✔
Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️
Ar(ABC)/Ar(DEF) = 64/ 121 --------(1)
As we know that, The Ratio of Similar triangle is equal to the square of the ratio pf yheir side.
=> AB/EF = (X/ 15.4)^2 -------(2)
FROM EQUATION 1 AND 2.
=> 64/121 = (X/15.4)^2
=> 8/ 11= X / 15.4
=> X = 15.4 × 8/11
=> x = 11.2cm✔✔
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