Question

let triangle PQR similar triangle XYZ and their areas be respectively 64cm square and 121cm square. If YZ = 15.4cm find QR?​

Answer 1

Answer:

As PQR is similar to XYZ

arPQR/ar XYZ = QR2/YZ2

64/121 = QR2/(15.4)2

sqrt of 64/121 as square of QR2/(15.4)2 comes on other side

So,

8/11 = QR/15.4

QR=8*15.4/11

QR = 11.2 ANSWER

Answer 2

Answer:

let QR=x

and ∆PQR~∆XYZ

Therefore, ar(∆PQR)/ar(∆XYZ)=(QR/YZ)^2

by theorem{if two triangle are similar then the proportion of their areas is equal to to the sum of square off there other sides }

so...

64/121 = (x/15.4)^2

64/121 = x^2/237.16

x^2 = 64×237.16/121

x^2 = 15178.24/121

x^2 = 1517824/12100

x = √(1517824/12100)

x = 1232/110

x = 11.2

therefore QR = 11.2

thanks for yours...