Question

let two curves are|y|=(x-1) (x-3)
and ly+1l = 2x+3 then number of points of
by intersection of these two curves in
1) First quadrant is 2.
2) fourth quadrant is 1
3) y axis is 1.
4) Third quadrant is 1
-
Please
answer this question​

Answer 1

Answer:

1) First Quadrant is 2

Step-by-step explanation:

Ignoring the modulas, if we write the curves as:

$y = 2x + 2 \\ y = {x}^{2} - 4x + 3$

For some value of x, both the equations will yield the same value for y.

$2x + 2 = {x}^{2} - 4x + 3 \\ {x}^{2} - 6x + 1 = 0$

Solving for x, we get,

$x = 3 + \sqrt{8} = 5.828 \\ x = 3 - \sqrt{8} = 0.171$

Both are the x coordinates of the points of intersections of both the curves. Hence the y coordinates will be,

$y = 2.343 \\ y = 13.657$

Since, the points of intersection lie in the first quadrant option (1) should be correct. Also, as the points lie in the first quadrant adding a modulas like in the original equations will make no difference.