Math, asked by inshahani, 5 months ago

let u={1,2,3,4,5,6,7,8} and A={2,4,6,8}B={248} then verify De-morgans law in intersection​

Answers

Answered by prashavisruth
1

Answer:

gn.

U={1,2,3,4,5,6,7,8}

A={2,4,6,8}

B={2,4,8}

De Morgan's law =A-(BUC)=(A-B)n(A-C)

first we find ( BUC)={2,5,8} U{2,4,8}

={2,4,5,8}

A-(BUC)={2,4,6,8,}-{2,45,8}

={6}

(A-B)={2,4,6,8}-{2,4,8}

={6}

(A-C)= {2,4,6,8}-{2,4,8}

={6}

De Morgan's law = {6}={6} n {6}

= {6} = {6}

hence it's proved.

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