Let U={1,2,3,...40}, A={x: x is divisible by 2 and 3} and B= {x:x= n^2 , n is a natural number}, then n(A) - n(B) is??
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Answered by
14
Answer:
U = { 1,2,3,...40 }
Elements of A are divisible by 2 and 3, it means these are divisible by 6.
So we can say,
A = { 6, 12, 18,...36 }
n(A) = 6, as 36 = 6*6
B contains squares of natural numbers. In between 1 and 40 -
B = { 1, 4, 9, 16, 25, 36 }
n(B) = 6
Hence,
= n(A) - n(B)
= 6 - 6
= 0
Answered by
0
Answer: 0
Step-by-step explanation:
U = { 1,2,3,...40 }
Elements of A are divisible by 2 and 3, it means these are divisible by 6.
So we can say,
A = { 6, 12, 18,...36 }
n(A) = 6, as 36 = 6*6
B contains squares of natural numbers. In between 1 and 40 -
B = { 1, 4, 9, 16, 25, 36 }
n(B) = 6
Hence,
= n(A) - n(B)
= 6 - 6
= 0
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