Question

Let U = {a, b, c, d, e, f, g}, A = {a, C,f,g}, B = {f,g,b,d}
(a) (A U B)' = (A' n B')this is intersection
answer fast pls​

Answer 1

Answer:

Step-by-step explanation:

U = {a, b, c, d, e, f, g}, A = {a, C,f,g}, B = {f,g,b,d}

AUB= { a,b,c,d,f,g}

(AUB)'=U - AUB= {e}---------------(1)

Now A'= U-A={ b,d,e}

B'=U-B={a,c,e}

A' ∩ B'= { b,d,e} ∩ { a,c,e}= {e}---------(2)

From (1) and (2)

(AUB)' = A' ∩ B'

hence proved