Question

let us arrange in ascending order
2^60, 3^48, 4^36, 5^24
​

Answer 1

Answer:

I calculated this.

It's already in ascending order

Plz mark me as brainliest

Answer 2

$\huge\mathfrak\color{purple}{Answer}$

As we know in this type of question we have to take the HCF of the powers so,

The HCF of 60,48,36,24 is 12

${2}^{60} = { {(2}^{5}) }^{12} = {(32)}^{12} \\ \\ {3}^{48} = { {(3}^{4}) }^{12} = {(81)}^{12} \\ \\ {4}^{36} = { {(4}^{3} )}^{12} = {(74)}^{12} \\ \\ {5}^{24} = { {(5}^{2} )}^{12} = {(25)}^{12} \\ \\ therefore \: \: \: \: {5}^{24} < {2}^{60} < {4}^{36} < {3}^{48}$

hope it helps u

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