Question

Let us calculate and write the value of k for which 2/3 will be a root the quadratic equation 7x^2+kx-3=0.​

Answer 1

∴ for k = ±216 given equation has equal roots.

Answer 2

Answer:

x=2/3

7(2/3)^2+(2/3)*k -3=0

7*(4/9) +(2k/3) -3 =0

28+6k-27=0. [taking LCM =9]

1+6k=0

6k= -1

k= -1/6

Hope it helps