let us calculate and write the value of k for which 2by3 will be A root the quadratic equation 7xsquare+kx-3
Answers
Answered by
88
Answer: k = -1/6
Given quadratic equation, 7x² + kx - 3 = 0 ; It is given that one of the two zeroes of this quadratic equation is 2/3.
These are just assumptions, with that, we have to find the value of k.
We know, zero of a quadratic equation is that value that satisfies the quadratic equation.
Which means,
x = 2/3 then,
⇒ 7(2/3)² + k(2/3) - 3 = 0
⇒ 7×4/9 + 2k/3 - 3 = 0
⇒ (28 + 6k - 27)/9 = 0
⇒ 1 + 6k = 0
⇒ 6k = -1
⇒ k = -1/6
Hence, The value of k is -1/6 for the given conditions.
Some Information :-
- A quadratic equation has two zeroes which can be real and distinct, imaginary, real and equal. This depends upon the discriminant of the quadratic equation which is given by,
⇒ D = b² - 4ac, where
- ax² + bx + c = 0 is the quadratic equation.
Also, if
D > 0
- Real and distinct roots exist.
D = 0
- Real and equal roots exist.
D < 0
- Imaginary roots.
Answered by
78
Given :-
Equation :-
To Find :-
Value of k
Solution :-
We need to just put the value of x to find k
k = -1/6
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