Math, asked by upashnasharmaupashna, 1 month ago

let us calculate the amount on RS 5000at the rate of 8%compound interest per

annum for 3years?​

Answers

Answered by mayajakhar79
2

Solution:-

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\large\to{\underbrace{\underline{\sf{Understanding\:the\:concept:-}}}}

\implies Here it is given in the question that we have to calculate the amount on Rs. 5000 at the rate of 8% compounded interest per annum for 3 years. Here we have to find out the amount and compound interest. So, to calculate the Amount and Compound Interest follow the steps shown below.

ANSWER:-

  • The amount is Rs. 6298.56.
  • The compound interest is Rs. 1298.56.

GIVEN:-

  • Principal amount = Rs. 5000
  • Rate of interest = 8%
  • Time = 3 years

TO FIND:-

  • Here we have to find out Amount and the Compound Interest.

SOLVING STEP BY STEP:-

  • To find the compound interest first we need to find the amount.
  • To find the amount we have to apply a certain formula.

We know that:-

\underline{ \boxed{\sf  \bigstar Amount = P\Bigg[1 + \bigg(\dfrac{R}{100} \bigg)^{n} \Bigg]}}

Where,

  • P = Principal
  • R = Rate
  • N = Time

-----------------------

  • Finding the amount:-

 \sf {Amount = 5000\Bigg[1 + \bigg(\dfrac{8}{100} \bigg)^{3} \Bigg]}

 \sf {Amount = 5000\bigg(\dfrac{100 + 8}{100} \bigg)^{3}}

 \sf {Amount = 5000\bigg(\dfrac{108}{100} \bigg)^{3}}

 \sf {Amount = 5000 \times  \dfrac{1259712}{1000000} }

 \sf {Cancelling \: the \: zeros. }

 \sf{Amount = 5 \times  \dfrac{1259712}{1000}}

 \sf{Multiplying \: the  \: terms}

 \sf{Amount = \dfrac{6298560}{1000}}

 \sf{Dividing \: 1000 \: by\:6298560.}

 \sf{Amount = \dfrac{6298560}{1000}} = 6298.56

\overline{ \boxed{\sf Amount = 6298.56}}

----------------------

  • Now, we will find the compound interest as we got the amount.

We know that:-

\underline{ \boxed{\sf  \bigstar Compound \: Interest = A - P}}

Where,

  • A = Amount
  • P = Principal

-----------------------

  • Finding the Compound Interest:-

\sf {Compound \: Interest = 6298.56 - 5000}

\sf {Compound \: Interest = 6298.56 - 5000 = 1298.56}

\overline{ \boxed{\sf Compound \:  Interest = 1298.56}}

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