Question

Let us consider a planet X with radius 3200 km, now we drop a ball from an
height of 10 m above the surface and it strikes the surface in 0.25 seconds. Find
128the mass of the planet X (Assume g=10 m/s2)

Answer 1

Answer:

h

1

=5m

h

2

=1.8

Velocity of ball just before hitting the ground =

2gh

1

=

10g

Velocity of ball just after hitting the ground =

2gh

2

=

3.6g

Loss in velocity=

10g

10g

−

3.6g

=1−

5

3

=

5

2