Let us consider a trapezium ABCD where AB is parallel to CD and two diagonals are drawn
which meet at the point O. if AO = 3cm, OC = 2cm, and OD = 6cm. Find the ratio between AB and
DC. pls tell
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Step-by-step explanation:
Given:
AB= 3cm, DC =6cm, CO= 4cm and OB=3cm
To find:
AO and DO.
Solution:
1) ABCD is the trapezium where the diagonals intersects at O.
2) We will do this question by using the property of the similarity of the triangle.
In ΔAOB & ΔCOD
∠1 = ∠5 (alternate interior angle)
∠2 = ∠4 (vertically opposite angle)
∠3 =∠6 (alternate interior angle)
so the triangles are similar by the AA similarity rule.
3) Apply the rule of similarity to find the ratios of the sides of the triangle.
Compare the ratios one by one
we get the value of y = 2 cm.
here we get the value x = 6 cm.
AO = 2 cm and DO = 6 cm.
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