Math, asked by hali3316, 1 year ago

Let us consider the offer to Usha who applied for a job and got selected. She has been offered a starting monthly salary of ₹8000, with an annual increment of ₹500. What would be her monthly salary of the fifth year?

Answers

Answered by mysticd
9
Hi ,

Starting Monthly salary of USHA= Rs8000

Annual salary of USHA = 12 × 8000

=Rs 96000

annual increment = Rs 500

Her annual salaries are

96000 , 96500 , 97000, ...

first term ( a1 ) = 96000

common difference ( d ) = a2 - a1

d = 96500 - 96000 = 500

Salary of 5th year = n = 6

an = a + ( n - 1 )d

a6 = 96000 + ( 6 - 1 )500

= 96000 + 5 × 500

= 96000 + 2500

= 98500

Now ,

monthly salary of fifth year = 98500/12

= Rs 8208.33

I hope this helps you.

: )







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