let us factorise x cube + y cube minus 12 X Y + 64
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Answer:
How do you find the value of x3+y3−12xy+64 when x+y=−4?
Precalculus
Explanation:
We know that
x3+y3x+y=x2−xy+y2 then
x3+y3=−4(x2−xy+y2) then
x3+y3−12xy+64=−4(x2−xy+y2)−12xy+64=
−4(x+y−4)(4+x+y)=0
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