Let us now add the digits of 21
2 + 1 = 3
5 +4=
3 + 6 =
6 + 3 =
All these sums are divisible by
Thus we can say that if the su
divisible by 3. Check this rule for oth
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yes all are divisible by3
Step-by-step explanation:
5+4=9/3=3
3+6=9/3=3
6+3=9/3=3
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