Math, asked by rishusinghofficial, 8 months ago

Let us now write some more numbers in exponential form :
(i)
 \sqrt{7}
(ii)
 \sqrt{11}
(iii)
( \sqrt{5) ^{3} }
(iiii)
( \sqrt[3]{13} ) ^{5}

Answers

Answered by hukam0685
0

Step-by-step explanation:

Given that:

 (I)\sqrt{7}

 (ii)\sqrt{11}

(iii)( \sqrt{5) ^{3} }

(iv)( \sqrt[3]{13} ) ^{5}

To find: Exponent form of given numbers

Solution : Exponent form ,i.e.

\bold{ {a}^{n} } \\

So,

 (i)\sqrt{7}  =  {7}^{ \frac{1}{2} }  \\

(ii) </p><p> \sqrt{11}  =  {(11)}^{ \frac{1}{2} }  \\

(iii)( \sqrt{5) ^{3} } \\ \\   =  &gt;   \sqrt{ {5}^{3} }  \\  \\  =  {( {5}^{3}) }^{ \frac{1}{2} }  \\  \\   \sqrt{ {5}^{3} }=  {5}^{ \frac{3}{2} }  \\  \\  \because \:  {( {a}^{b} )}^{ \frac{1}{n} }  =  {a}^{ \frac{b}{n} }  \\  \\

(iv)( \sqrt[3]{13} ) ^{5} \\  \\  =  &gt;  ({( {13)}^{ \frac{1}{3} } })^{5}  \\  \\ ( \sqrt[3]{13} ) ^{5} =   {(13)}^{ \frac{5}{3} }  \\  \\

Hope it helps you.

Answered by Geetapal0777
0

Let us now write some more numbers in exponential form :

(i)

 \sqrt{7}

(ii)

 \sqrt{11}

(iii)

( \sqrt{5) ^{3} }

(iiii)

( \sqrt[3]{13} ) ^{5}

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