Question

Let us prove that the point(-2, - 11) is equidistant from the two points (-3,7) and (4,6)​

Answer 1

Step-by-step explanation:

We know that distance between two points (x1, y1) and (x2, y2) is given that

√(x2-x1)²+(y2-y1)²

Using the above distance formula,

Distance between (–2, –11) and (-3, 7)

√(-1)²+(18)²

=√1+324=√325

=5√13

Distance between (–2, –11) and (4, 6)

√(6)²+(17)²

=√36+289

=√325

=5√13

Hence proved that the point (–2, –11) is equidistant from the two points (–3, 7) and (4, 6)