Question

Let us prove that the three points A (3, 3), B (8,-2) and C (-2,-2) are the vertices of a right-angled isosceles triangle. Let us calculate the length of the hypotenuse of AABC.

Answer 1

Answer: please mark me brainlist

Step-by-step explanation:

AB = $\sqrt{(8-3)^{2} +(-2-3)^{2} } = \sqrt{(5)^{2}+(-5)^{2} } =\sqrt{25+25} = \sqrt{50} = 5\sqrt{2}$

BC = $\sqrt{(-2-8)^{2} + (-2+2)^{2} } = \sqrt{100} = 10 units$

CA = $\sqrt{(3+2)^{2} + (3+2)^{2} } = \sqrt{25+25} = \sqrt{50} = 5\sqrt{2}$

THEREFORE AB and CA are same the above points are a vertices on a right angeled traingle